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JEE MAIN 2019 Answer Key – Important Dates, Downloading Procedure, Past and Expected Cut-Off

The self-sustaining body called NTA (National Testing agency) incorporated by the Ministry of Human Resource Development has announced officially that it will take charge of conducting the JEE MAIN 2019 twice a year. The exam will take place once on January 6th to 20th, 2019 and second on Feb 8th to Mar 7th, 2019. The exam is conducted to help students acquire seats of dream courses like B.Tech, B.E, B.Planning, and B. Arch in the prestigious colleges. The courses are offered by the varied institutes – IITs, IIITs, NIITs and other govt. and non-govt. institutes.

The JEE MAIN answer keys 2019 will be released via online mode in order to help candidates know their potential result and expected cut-off in advance itself. Separate keys will be released for paper 1 (B.E/B.Tech) and paper 2 (B.Arch/ B.Planning). With the release of the answer keys, the candidates can easily calculate their chances of getting the right opportunity instead of waiting for the final results. Students can easily check their progress beforehand with the help of tools like rank predictor and score calculator. The following article will give detailed information about the JEE MAIN 2019 answer keys release date, download procedure, past cut off and other important information related to the exam.

JEE MAIN 2019 Answer keys

After the completion of the Joint Entrance Exam MAIN exam, students can expect the release of the provisional answer key by various institutes. However, the final key will be released by The Agency at nta.ac.in

This way, students will get a rough idea about how much they would score in the exam.

JEE Main 2019 Release Dates

The answer keys are likely to be released in the month of January 2019 for the January session for both paper 1 and 2 and in the month of April 2019 for the April session for both paper 1 and 2 of JEE MAIN 2019.

JEE MAIN 2019 Answer Key Downloading Procedure

The candidates who are looking forward to a brief procedure of downloading their respective exam’s answer key must refer to the following points:

  • The students first have to visit the official website of NTA at nta.ac.in
  • Then click on the answer key link and open it.
  • Enter the application number, password along with a security pin.
  • Press the login button.
  • They can then get access to the answer keys of the different sets – A, B, C and D
  • The candidate must save the answer key and keep it for future reference.

Can Candidates Challenge JEE MAIN 2019 Answer Key?

Yes, it is possible for candidates to propose a challenge to the officials of the examination if they are not satisfied with the released answer key. The candidates can easily challenge it by filling the online application form. For this, they will have to pay Rs. 1000 per question. No candidate’s appeal shall be considered for the challenge if they do it in person or by post as the process is only online.

The candidates can challenge the release of JEE MAIN 2019 answer key in the month of January 2019 (Jan session) and in April 2019 (April session). However, there is no guarantee that the result of the challenge will be in candidates favour. Thus, candidates must only appeal if they are confident in their approach.

The Minimum Cut Off For JEE Main 2019

The candidates based on their score in JEE main 2019 will get a rank. The colleges will be releasing the cut off based on the result of the candidates. The cut off will be released along with the final result by the officials of the exam. Below are illustrated the past years’ cut off:

Year Registered Candidates UR Cut off SC Cut off ST Cut off OBC Cut off
2017 11.9 Lakh

 

81 32 27 49
2016 12 Lakh 100 52 48 70
2015 13 Lakh 105 50 44 70
2014 13 Lakh 115 53 47 74

Procedure to Obtain the OMR Sheet for JEE MAIN 2019

The candidates who wish to challenge the answer key can request the officials for providing the fresh OMR sheet along with a separate calculation sheet for the improvised answers. The students need to pay a sum of Rs. 500 via bank draft in order to acquire the sheet. The students must mention their name, application number and roll no. at the back of the draft to avoid the loss.

How to use the answer key for the JEE MAIN 2019?

The best part about the answer key is that students can easily assume their score without waiting for the actual results. The keys were devised with an aim to help students from soiling their time until the actual results are out and know their potential beforehand. Here are a few steps that would help you to use the answer key of JEE MAIN 2019 effectively:

  • Download the answer key from the official website of NTA as soon as it is released.
  • Match your answers (given in the exam) with the released answer key.
  • Follow the correct marking scheme strictly mentioned by the officials. There is +4 and -1 marking scheme at present.
  • Calculate the total number of marks by totalling all the numbers and deducting the negative marks for every wrong selection.

Check out: JEE Main 2019 Result

JEE MAIN 2019 Marking Scheme

There is negative marking scheme in the Joint Entrance Test Main 2019. For every correct answer, an applicant would get 4 marks. In case of an incorrect answer, 1 mark would be deducted.

S.No. Answer Category Marking scheme
1. Correct selection 4 marks will be awarded
2. Incorrect selection 1 mark deduction
3. No selection No marks
4. More than one selection 1 mark deduction

Conclusion

A provisional answer key will be released first by the officials, thereafter, students will be provided with plenty of time to raise an objection. The candidates have to fill in the application along with the requisite fee to have an access to OMR and solution sheet. The students will be given a certain period of time to present their preferred solutions. After receiving the entries of preferred answers from the candidates, the authority/ officials of the exam will go through each and every answer received. The officials after a while will release the final statement of the answer key/ response sheet, which will not be liable to get objected at any cost. Therefore, students must apply for the challenge only if they are sure.

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